16x^2-4x+(1/4)=0

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Solution for 16x^2-4x+(1/4)=0 equation:



16x^2-4x+(1/4)=0
We add all the numbers together, and all the variables
16x^2-4x+(+1/4)=0
We get rid of parentheses
16x^2-4x+1/4=0
We multiply all the terms by the denominator
16x^2*4-4x*4+1=0
Wy multiply elements
64x^2-16x+1=0
a = 64; b = -16; c = +1;
Δ = b2-4ac
Δ = -162-4·64·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{16}{128}=1/8$

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